Integrand size = 17, antiderivative size = 96 \[ \int \left (c+e x^2\right ) \left (a+b x^4\right )^p \, dx=c x \left (a+b x^4\right )^p \left (1+\frac {b x^4}{a}\right )^{-p} \operatorname {Hypergeometric2F1}\left (\frac {1}{4},-p,\frac {5}{4},-\frac {b x^4}{a}\right )+\frac {1}{3} e x^3 \left (a+b x^4\right )^p \left (1+\frac {b x^4}{a}\right )^{-p} \operatorname {Hypergeometric2F1}\left (\frac {3}{4},-p,\frac {7}{4},-\frac {b x^4}{a}\right ) \]
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Time = 0.03 (sec) , antiderivative size = 96, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.294, Rules used = {1218, 252, 251, 372, 371} \[ \int \left (c+e x^2\right ) \left (a+b x^4\right )^p \, dx=c x \left (a+b x^4\right )^p \left (\frac {b x^4}{a}+1\right )^{-p} \operatorname {Hypergeometric2F1}\left (\frac {1}{4},-p,\frac {5}{4},-\frac {b x^4}{a}\right )+\frac {1}{3} e x^3 \left (a+b x^4\right )^p \left (\frac {b x^4}{a}+1\right )^{-p} \operatorname {Hypergeometric2F1}\left (\frac {3}{4},-p,\frac {7}{4},-\frac {b x^4}{a}\right ) \]
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Rule 251
Rule 252
Rule 371
Rule 372
Rule 1218
Rubi steps \begin{align*} \text {integral}& = \int \left (c \left (a+b x^4\right )^p+e x^2 \left (a+b x^4\right )^p\right ) \, dx \\ & = c \int \left (a+b x^4\right )^p \, dx+e \int x^2 \left (a+b x^4\right )^p \, dx \\ & = \left (c \left (a+b x^4\right )^p \left (1+\frac {b x^4}{a}\right )^{-p}\right ) \int \left (1+\frac {b x^4}{a}\right )^p \, dx+\left (e \left (a+b x^4\right )^p \left (1+\frac {b x^4}{a}\right )^{-p}\right ) \int x^2 \left (1+\frac {b x^4}{a}\right )^p \, dx \\ & = c x \left (a+b x^4\right )^p \left (1+\frac {b x^4}{a}\right )^{-p} \, _2F_1\left (\frac {1}{4},-p;\frac {5}{4};-\frac {b x^4}{a}\right )+\frac {1}{3} e x^3 \left (a+b x^4\right )^p \left (1+\frac {b x^4}{a}\right )^{-p} \, _2F_1\left (\frac {3}{4},-p;\frac {7}{4};-\frac {b x^4}{a}\right ) \\ \end{align*}
Time = 0.43 (sec) , antiderivative size = 75, normalized size of antiderivative = 0.78 \[ \int \left (c+e x^2\right ) \left (a+b x^4\right )^p \, dx=\frac {1}{3} x \left (a+b x^4\right )^p \left (1+\frac {b x^4}{a}\right )^{-p} \left (3 c \operatorname {Hypergeometric2F1}\left (\frac {1}{4},-p,\frac {5}{4},-\frac {b x^4}{a}\right )+e x^2 \operatorname {Hypergeometric2F1}\left (\frac {3}{4},-p,\frac {7}{4},-\frac {b x^4}{a}\right )\right ) \]
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\[\int \left (e \,x^{2}+c \right ) \left (b \,x^{4}+a \right )^{p}d x\]
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\[ \int \left (c+e x^2\right ) \left (a+b x^4\right )^p \, dx=\int { {\left (e x^{2} + c\right )} {\left (b x^{4} + a\right )}^{p} \,d x } \]
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Result contains complex when optimal does not.
Time = 17.25 (sec) , antiderivative size = 75, normalized size of antiderivative = 0.78 \[ \int \left (c+e x^2\right ) \left (a+b x^4\right )^p \, dx=\frac {a^{p} c x \Gamma \left (\frac {1}{4}\right ) {{}_{2}F_{1}\left (\begin {matrix} \frac {1}{4}, - p \\ \frac {5}{4} \end {matrix}\middle | {\frac {b x^{4} e^{i \pi }}{a}} \right )}}{4 \Gamma \left (\frac {5}{4}\right )} + \frac {a^{p} e x^{3} \Gamma \left (\frac {3}{4}\right ) {{}_{2}F_{1}\left (\begin {matrix} \frac {3}{4}, - p \\ \frac {7}{4} \end {matrix}\middle | {\frac {b x^{4} e^{i \pi }}{a}} \right )}}{4 \Gamma \left (\frac {7}{4}\right )} \]
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\[ \int \left (c+e x^2\right ) \left (a+b x^4\right )^p \, dx=\int { {\left (e x^{2} + c\right )} {\left (b x^{4} + a\right )}^{p} \,d x } \]
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\[ \int \left (c+e x^2\right ) \left (a+b x^4\right )^p \, dx=\int { {\left (e x^{2} + c\right )} {\left (b x^{4} + a\right )}^{p} \,d x } \]
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Timed out. \[ \int \left (c+e x^2\right ) \left (a+b x^4\right )^p \, dx=\int {\left (b\,x^4+a\right )}^p\,\left (e\,x^2+c\right ) \,d x \]
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